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Find whether the given number is Armstrong or not

 # Armstrong Number -- * Aim = To find the given number is Armstrong number or not. Q.) What is an Armstrong number? Ans.) It is a number where sum of cube of its digit is equal to the given number.  For example==>> Say 407 then-- (4)³+(0)³+(7)³ = 64 + 0 + 343 = 407 # code : actual = int(input('Enter number:')) sum = 0 num = actual  while (num>0):     digit = (num%10)      power = pow(digit,3)      sum = sum + power      num = num//10 if (sum==actual):     print( actual , 'is an Armstrong number') else:     print( actual , 'is not an Armstrong number') # Output : Enter number:407                     407 is an Armstrong number >> Lets look how the code works : 1) First, get input from the user. 2) Then initialize the variable. 3) Store the actual (input) in a variable called num . We do this coz at the end we need to compare the sum with the actual input. If we don't do this our actual input will keep on decrementing and we'll not