code feat

 # Armstrong Number -- * Aim = To find the given number is Armstrong number or not. Q.) What is an Armstrong number? Ans.) It is a number where sum of cube of its digit is equal to the given number.  For example==>> Say 407 then-- (4)³+(0)³+(7)³ = 64 + 0 + 343 = 407 # code : actual = int(input('Enter number:')) sum = 0 num = actual  while (num>0):     digit = (num%10)      power = pow(digit,3)      sum = sum + power      num = num//10 if (sum==actual):     print( actual , 'is an Armstrong number') else:     print( actual , 'is not an Armstrong number') # Output : Enter number:407                     407 is an Armstrong number >> Lets look how the code works : 1) First, get input from the user. 2) Then initialize the variable. 3) Store the actual (input) in a variable called num . We do this coz at the end we need to compare the sum with the actual input. If we don't do this our actual input will keep on decrementing and we'll not

* Our objective is to find the sum of given digits i.e.; 2+4+3=9 # sum of given digits code :-- n = int(input('Enter number:')) sum =0 while n>0:     sum = sum + (n%10)     n = n//10 print('Sum of digits=', sum) # Output : Enter number:243                 Sum of digits= 9 >> Lets look at the program-- 1) First we'll take an input from the user    Say n = 243 2) Secondly, we'll initialize the variable    sum = 0 3) We'll build a loop    i.e.; while n>0: 4) Now we'll build our logic as    sum = sum + (n%10)         ----eq.1 >> Lets see how this logic works-- Here, at the R.H.S we have sum + (n%10)     ----from eq.1 Since we have sum=0 and n=243 Therefore, sum + (n%10) = 0 + (243%10)  >> When we divide 243/10 we get the remainder as 3. That is what 243%10 is doing here.               = 0 + (3)                                     sum = 3 >> We have fetched the last digit from the given number. But now we want th